The hydrolysis constants of salts NaA and NaB | vedclass

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(A) The hydrolysis constant $K_h$ for a salt of a weak acid and strong base is given by $K_h = \frac{K_w}{K_a}$.For $NaA$: $K_h(A^-) = 10^{-8} = \frac

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$HB > HC > HA$

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(A) The hydrolysis constant $K_h$ for a salt of a weak acid and strong base is given by $K_h = \frac{K_w}{K_a}$.For $NaA$: $K_h(A^-) = 10^{-8} = \frac{10^{-14}}{K_a(HA)}$,so $K_a(HA) = 10^{-6}$.For $NaB$: $K_h(B^-) = 10^{-10} = \frac{10^{-14}}{K_a(HB)}$,so $K_a(HB) = 10^{-4}$.For $HC$: $K_a(HC) = 10^{-5}$.Comparing the dissociation constants: $K_a(HB) = 10^{-4} > K_a(HC) = 10^{-5} > K_a(HA) = 10^{-6}$.Since acidic strength is directly proportional to $K_a$,the order is $HB > HC > HA$.

The hydrolysis constants of salts $NaA$ and $NaB$ (of weak acids $HA$ and $HB$) are $10^{-8}$ and $10^{-10}$ respectively. If the dissociation constant of weak acid $HC$ is $10^{-5}$,what is the decreasing order of acidic strength?

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