The concentration of [{H^ + }] and concentrat | vedclass

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Question

(a) Given that

Concentration of solution $ =0.1$

Degree of ionisation $ = 2\% = \frac{2}{{100}} = 0.02$

Ionic product of water $ = 1 	imes {

Vedclass · Accepted Answer

$2 	imes {10^{ - 3}}$ $M$ and $5 	imes {10^{ - 12}}$ $M$

Vedclass · Answer

(a) Given that

Concentration of solution $ =0.1$

Degree of ionisation $ = 2\% = \frac{2}{{100}} = 0.02$

Ionic product of water $ = 1 	imes {10^{ - 14}}$

Concentration of $[{H^ + }]$= Concentration of solution $	imes$ degree of ionisation $ = 0.1 	imes 0.02 = 2 	imes {10^{ - 3}}M$

Concentration of $[O{H^ - }] = \frac{{{m{Ionic product of water}}}}{{[{H^ + }]}}$

$ = \frac{{1 	imes {{10}^{ - 14}}}}{{2 	imes {{10}^{ - 3}}}} = 0.5 	imes {10^{ - 11}} = 5 	imes {10^{ - 12}}M$.

The concentration of $[{H^ + }]$ and concentration of $[O{H^ - }]$ of a $ 0.1$ aqueous solution of $2\%$ ionised weak acid is [Ionic product of water $ = 1 \times {10^{ - 14}}]$

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