The pair of equations 5x - 15y = 8 and 3x - 9 | vedclass

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(A) Given equations are:$5x - 15y = 8$  --- $(1)$$3x - 9y = \frac{24}{5}$  --- $(2)$Comparing these with the standard form $a_1x + b_1y = c_1$ and $a_

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infinitely many solutions

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(A) Given equations are:$5x - 15y = 8$  --- $(1)$$3x - 9y = \frac{24}{5}$  --- $(2)$Comparing these with the standard form $a_1x + b_1y = c_1$ and $a_2x + b_2y = c_2$:$a_1 = 5, b_1 = -15, c_1 = 8$$a_2 = 3, b_2 = -9, c_2 = \frac{24}{5}$Now,calculate the ratios:$\frac{a_1}{a_2} = \frac{5}{3}$$\frac{b_1}{b_2} = \frac{-15}{-9} = \frac{5}{3}$$\frac{c_1}{c_2} = \frac{8}{24/5} = \frac{8 	imes 5}{24} = \frac{40}{24} = \frac{5}{3}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} = \frac{5}{3}$,the lines are coincident.Therefore,the pair of equations has infinitely many solutions.

The pair of equations $5x - 15y = 8$ and $3x - 9y = \frac{24}{5}$ has

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