The output sinusoidal current versus time curve of a rectifier is shown in the figure. The average value of output current in this case is

An alternating voltage $\mathrm{V}(\mathrm{t})=220 \sin 100 \ \pi \mathrm{t}$ volt is applied to a purely resistive load of $50\ \Omega$. The time taken for the current to rise from half of the peak value to the peak value is:

An alternating voltage $V = 300\sqrt 2 sin(100t)$ is connected to a $1\ \mu F$ capacitor through an $AC$ ammeter. The reading of the ammeter will be.....$mA$

The voltage of $AC$ source varies with time according to the equation, $V = 100\, \sin 100\, \pi \, t \, \cos \,100\, \pi \,t$. Where $t$ is in second and $V$ is in volt. Then:-

An $AC$ current is given by $I = I_0 + I_1$ $sin\, wt$ then its $rms$ value will be

Match the following

Currents                                     $r.m.s.$ values

(1)${x_0}\sin \omega \,t$                               (i)$ x_0$

(2)${x_0}\sin \omega \,t\cos \omega \,t$                  (ii)$\frac{{{x_0}}}{{\sqrt 2 }}$

(3)${x_0}\sin \omega \,t + {x_0}\cos \omega \,t$        (iii) $\frac{{{x_0}}}{{(2\sqrt 2 )}}$