An alternating voltage $\mathrm{V}(\mathrm{t})=220 \sin 100 \ \pi \mathrm{t}$ volt is applied to a purely resistive load of $50\ \Omega$. The time taken for the current to rise from half of the peak value to the peak value is:

In $ac$ circuit when $ac$ ammeter is connected it reads $i$ current if a student uses $dc$ ammeter in place of $ac$ ammeter the reading in the $dc$ ammeter will be:

A $40$ $\Omega$ electric heater is connected to a$ 200 V, 50 Hz$ mains supply. The peak value of electric current flowing in the circuit is approximately......$A$

Find the rms value for the saw-tooth voltage of peak value $V_0$ from $t = 0$ to $t = 2T$ as shown in figure

A direct current of $10 \,A$ is superimposed on an alternating current $I=40 \cos \omega t\;( A )$ flowing through a wire. The effective value of the resulting current will be ....... $A$

The current flowing through an ac circuit is given by

$I=5 \sin (120 \pi t) A$

How long will the current take to reach the peak value starting from zero?