An alternating voltage $V(t) = 220 \sin(100 \pi t)$ volt is applied to a purely resistive load of $50 \ \Omega$. The time taken for the current to rise from half of the peak value to the peak value is: (in $ms$)

Let $f = 50\, Hz$ and $C = 100\, \mu F$ in an $AC$ circuit containing a capacitor only. If the peak value of the current in the circuit is $1.57\, A$,the expression for the instantaneous voltage across the capacitor will be (assuming current is $I = I_m \sin(\omega t)$):

An $A.C.$ voltage is applied to a pure inductor. The current in the inductor

The reactance of a $25\,\mu F$ capacitor at the ac frequency of $4000\, Hz$ is

The coil of inductance $0.25 mH$ has a reactance of $330 \Omega$,when connected to an a.c. source. The frequency of the a.c. source is (Take $\pi = \frac{22}{7}$) (in $kHz$)

$A$ capacitor of $50 \mu F$ is connected to a power source $V = 220 \sin 50 t$ (where $V$ is in volt and $t$ is in second). Find the value of the $rms$ current (in ampere).