The voltage of $AC$ source varies with time according to the equation, $V = 100\, \sin 100\, \pi \, t \, \cos \,100\, \pi \,t$. Where $t$ is in second and $V$ is in volt. Then:-

  • A

    The peak voltage of the source is $100\, volt$

  • B

    The peak voltage of the sourece is $(100/ \sqrt 2 )\, volt$

  • C

    the peak voltage of the source is $50\, volt$

  • D

    The frequency of the source is $50\, Hz$

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