The osmotic pressure of blood is 7.47 , bar a | vedclass

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(C) The formula for osmotic pressure is $\pi = C 	imes R 	imes T$,where $C$ is the molar concentration in $mol \, L^{-1}$.Given $\pi = 7.47 \, bar$,

Vedclass · Accepted Answer

$54$

Vedclass · Answer

(C) The formula for osmotic pressure is $\pi = C 	imes R 	imes T$,where $C$ is the molar concentration in $mol \, L^{-1}$.Given $\pi = 7.47 \, bar$,$R = 0.083 \, L \, bar \, K^{-1} \, mol^{-1}$,and $T = 300 \, K$.Substituting the values: $7.47 = C 	imes 0.083 	imes 300$.$C = \frac{7.47}{0.083 	imes 300} = \frac{7.47}{24.9} = 0.3 \, mol \, L^{-1}$.To find the concentration in $g \, L^{-1}$,multiply the molar concentration by the molar mass of glucose $(180 \, g \, mol^{-1})$:$	ext{Concentration} = 0.3 \, mol \, L^{-1} 	imes 180 \, g \, mol^{-1} = 54 \, g \, L^{-1}$.

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