The osmotic pressure of a 5% (wt/vol) solutio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The osmotic pressure $\pi$ is given by the formula $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant $(0.082 \ L \ atm \ K^

Vedclass · Accepted Answer

$5.08$

Vedclass · Answer

(B) The osmotic pressure $\pi$ is given by the formula $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant $(0.082 \ L \ atm \ K^{-1} \ mol^{-1})$,and $T$ is the temperature in Kelvin.$1.$ Calculate the molar concentration $(C)$: $A$ $5\%$ (wt/vol) solution means $5 \ g$ of cane sugar ($C_{12}H_{22}O_{11}$,molar mass $= 342 \ g/mol$) in $100 \ mL$ of solution.$C = \frac{5 \ g}{342 \ g/mol} 	imes \frac{1000 \ mL/L}{100 \ mL} = \frac{50}{342} \ mol/L \approx 0.1462 \ mol/L$.$2.$ Convert temperature to Kelvin: $T = 150 + 273 = 423 \ K$.$3.$ Calculate osmotic pressure: $\pi = (\frac{50}{342} \ mol/L) 	imes (0.082 \ L \ atm \ K^{-1} \ mol^{-1}) 	imes (423 \ K) \approx 5.07 \ atm$.Thus,the closest value is $5.08 \ atm$.

The osmotic pressure of a $5\%$ (wt/vol) solution of cane sugar at $150\,^{\circ}C$ is $......... \ atm$.

Similar Questions

Equal volumes of $0.2 \ M$ urea and $0.2 \ M$ glucose are mixed. The mixture will have

$\pi = \text{..........}$

The swelling in feet and ankles of an aged person due to sitting continuously for long hours during travel,is reduced by soaking the feet in warm salt water. This is because of

$A$ $1.17 \%$ solution of solute $A$ is isotonic with a $7.2 \%$ solution of glucose. If the molecular weight of solute $A$ is $58.5$,the value of the van't Hoff factor,'$i$',is:

$0.2 \ M$ aqueous solution of glucose has osmotic pressure $4.9 \ atm$ at $300 \ K$. What is the concentration of glucose if it has osmotic pressure $1.5 \ atm$ at same temperature (in $M$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module