The number of values of x in the interval [0, | vedclass

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Question

$3 \sin ^{2} x-7 \sin x+2=0$

$\Rightarrow \quad(3 \sin x-1)(\sin x-2)=0$

$\Rightarrow \quad 3 \sin x=1$ or $\quad \sin x=2$

$\Rightarrow \qua

Vedclass · Accepted Answer

$6$

Vedclass · Answer

$3 \sin ^{2} x-7 \sin x+2=0$

$\Rightarrow \quad(3 \sin x-1)(\sin x-2)=0$

$\Rightarrow \quad 3 \sin x=1$ or $\quad \sin x=2$

$\Rightarrow \quad \sin x=\frac{1}{3} \quad[\because \sin x=2 	ext { is not possible }]$

since $x \in[0,5 \pi]$

$	herefore $ $6$ values of $x$ will be possible.

[$\because x$ will lie in ${I^{st}}{m{ }}or{m{ }}I{I^{nd}}$ quadrant]

The number of values of $x$ in the interval $[0, 5\pi]$ satisfying the equation $3sin^2x\, \,-\,\, 7sinx + 2 = 0$ is

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