The number of unpaired electrons in a ferrous | vedclass

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(B) The atomic number of iron $(Fe)$ is $26$.The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms a ferrous ion $(Fe^{2+})$,it los

Vedclass · Accepted Answer

$4$

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(B) The atomic number of iron $(Fe)$ is $26$.The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms a ferrous ion $(Fe^{2+})$,it loses two electrons from the $4s$ orbital.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the $3d$ subshell,there are $5$ orbitals. According to Hund's rule,the $6$ electrons are filled as follows: $4$ orbitals contain $1$ electron each,and $1$ orbital contains $2$ electrons.Therefore,the number of unpaired electrons in $Fe^{2+}$ is $4$.

The number of unpaired electrons in a ferrous ion $(Fe^{2+})$ is:

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