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Let the coefficients of powers of $x$ in the $2nd$,$3rd$,and $4th$ terms in the expansion of $(1+x)^{n}$,where $n$ is a positive integer,be in arithmetic progression. Then,the sum of the coefficients of odd powers of $x$ in the expansion is

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The constant term in the expansion of $\left(\frac{x}{2}+\frac{1}{x}+\sqrt{2}\right)^5$ is $\frac{a \sqrt{2}}{2}$,then $a=$

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