The number of possible enantiomeric pair(s) p | vedclass

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Question

(a)
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Bromination of compound $I$ will give a $meso$ product. So, will not have any enantiomer product, but bromination of compound $II$ giv

Vedclass · Accepted Answer

$0,1$

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(a)
$[Image]$
Bromination of compound $I$ will give a $meso$ product. So, will not have any enantiomer product, but bromination of compound $II$ gives a chiral compound, hence its two form $d$ and $l$ are possible, which are mirror images of each other and are non-superimposable. It's other enantiomeric form will be
$\begin{matrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}  \ \,\,\,\,\,\,\,\,\,|  \ C{{H}_{2}}Br-C-Br  \ \,\,\,\,\,\,\,\,\,\,|  \ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}}  \ \end{matrix}$
So, it will have one enantiomeric pair. Thus, correct option is $(a).$

The number of possible enantiomeric pair(s) produced from the bromination of $I$ and $II,$ respectively, are

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