Which L -sugar on oxidation gives an opticall | vedclass

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Question

Any sugar will be optically active when it does not have any plane of symmetry.

As only $(a)$ and $(d)$ are $L$-sugar, $(b)$ and $(c)$ are $D$-suga

Vedclass · Accepted Answer

Vedclass · Answer

Any sugar will be optically active when it does not have any plane of symmetry.

As only $(a)$ and $(d)$ are $L$-sugar, $(b)$ and $(c)$ are $D$-sugar after oxidation.

$(a)$ (Refer to Image $1$)

As the product do not superimpose in its mirror image.

$(d)$ (Refer to Image $2$)

As it has plane of symmetry.

Which $L$ -sugar on oxidation gives an optically active dibasic acid

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