The maximum number of stereoisomers that coul | vedclass

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(C) The structure of the compound is $CH_3-CH(Br)-CH(Br)-CH(Br)-CH(Br)-CH_3$. There are $n = 4$ chiral centers. The molecule is symmetrical. For a sym

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$10$

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(C) The structure of the compound is $CH_3-CH(Br)-CH(Br)-CH(Br)-CH(Br)-CH_3$. There are $n = 4$ chiral centers. The molecule is symmetrical. For a symmetrical molecule with an even number of chiral centers $(n)$,the total number of stereoisomers is given by the formula: Total stereoisomers $= 2^{n-1} + 2^{(n/2)-1}$. Substituting $n = 4$: Total stereoisomers $= 2^{4-1} + 2^{(4/2)-1} = 2^3 + 2^1 = 8 + 2 = 10$. Thus,the correct option is $(c)$.

The maximum number of stereoisomers that could exist for the compound $2,3,4,5$-tetrabromohexane is:

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