The number of photons emitted per second by a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The power $P$ of the bulb is the total energy emitted per second. The energy of a single photon is given by $E = \frac{hc}{\lambda}$.If $n$ is the

Vedclass · Accepted Answer

$2 	imes 10^{20}$

Vedclass · Answer

(D) The power $P$ of the bulb is the total energy emitted per second. The energy of a single photon is given by $E = \frac{hc}{\lambda}$.If $n$ is the number of photons emitted per second,then the total power is $P = n 	imes E = n \frac{hc}{\lambda}$.Rearranging for $n$,we get $n = \frac{P \lambda}{hc}$.Given: $P = 66 \ W$,$\lambda = 600 \ nm = 600 	imes 10^{-9} \ m$,$h = 6.6 	imes 10^{-34} \ J \cdot s$,and $c = 3 	imes 10^8 \ m/s$.Substituting the values:$n = \frac{66 	imes 600 	imes 10^{-9}}{6.6 	imes 10^{-34} 	imes 3 	imes 10^8}$$n = \frac{66 	imes 600 	imes 10^{-9}}{19.8 	imes 10^{-26}}$$n = \frac{39600 	imes 10^{-9}}{19.8 	imes 10^{-26}}$$n = 2000 	imes 10^{17} = 2 	imes 10^{20}$.Thus,the number of photons emitted per second is $2 	imes 10^{20}$.

The number of photons emitted per second by a bulb of $66 \ W$ power emitting waves of wavelength $600 \ nm$ is . . . . . . . $(h = 6.6 \times 10^{-34} \ J \cdot s)$

Similar Questions

Can a quantum of light be associated with a particle?

$A$ bulb has a power of $60 \, mW$ and emits light of wavelength $6000 \, \mathring{A}$. Calculate the number of photons emitted by the bulb per second.

Which of the following will have the least value of $\frac{q}{m}$?

The fact that photons carry energy was established by

Write the characteristics of a photon or how can a photon of electromagnetic radiation be represented?

Vedclass Test Series

Exam Paper Generator

Online Exam Module