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(C) The specific charge is defined as the ratio of charge to mass,denoted by $\frac{q}{m}$.For an electron,$q = e$ and $m = m_e$.For a proton,$q = e$

Vedclass · Accepted Answer

$\alpha$-particle

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(C) The specific charge is defined as the ratio of charge to mass,denoted by $\frac{q}{m}$.For an electron,$q = e$ and $m = m_e$.For a proton,$q = e$ and $m = 1836 m_e$.For an $\alpha$-particle,$q = 2e$ and $m = 4 m_p \approx 7344 m_e$.For a $\beta$-particle,it is an electron,so $q = e$ and $m = m_e$.Comparing the ratios:Electron: $\frac{e}{m_e}$Proton: $\frac{e}{1836 m_e}$$\alpha$-particle: $\frac{2e}{7344 m_e} = \frac{e}{3672 m_e}$$\beta$-particle: $\frac{e}{m_e}$Since the denominator is largest for the $\alpha$-particle,the value of $\frac{q}{m}$ is the least for the $\alpha$-particle.

Which of the following will have the least value of $\frac{q}{m}$?

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