The number of paramagnetic complexes among [F | vedclass

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(A) To determine the hybridization and magnetic nature,we analyze the oxidation state of the metal and the nature of the ligand:ComplexHybridizationMa

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$2$

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(A) To determine the hybridization and magnetic nature,we analyze the oxidation state of the metal and the nature of the ligand:ComplexHybridizationMagnetic Nature$[FeF_6]^{3-}$$sp^3d^2$Paramagnetic$[Fe(CN)_6]^{3-}$$d^2sp^3$Paramagnetic$[Mn(CN)_6]^{3-}$$d^2sp^3$Paramagnetic$[Co(C_2O_4)_3]^{3-}$$d^2sp^3$Diamagnetic$[MnCl_6]^{3-}$$sp^3d^2$Paramagnetic$[CoF_6]^{3-}$$sp^3d^2$ParamagneticFrom the table,the complexes that involve $d^2sp^3$ hybridization are $[Fe(CN)_6]^{3-}, [Mn(CN)_6]^{3-}$,and $[Co(C_2O_4)_3]^{3-}$.Among these,$[Fe(CN)_6]^{3-}$ and $[Mn(CN)_6]^{3-}$ are paramagnetic.Therefore,the number of such complexes is $2$.

Column-$I$ Complex	Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$	$I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$	$II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$	$III$. Square planar / Diamagnetic

The number of paramagnetic complexes among $[FeF_6]^{3-}, [Fe(CN)_6]^{3-}, [Mn(CN)_6]^{3-}, [Co(C_2O_4)_3]^{3-}, [MnCl_6]^{3-}$,and $[CoF_6]^{3-}$ that involve $d^2sp^3$ hybridization is ....................

Similar Questions

$A$ square planar complex is formed by the hybridization of which atomic orbitals?

Which of the following hybrid states is associated with a low spin octahedral complex?

Match the following:

Column-$I$ Complex Column-$II$ Structure / Geometry / Property

$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic

$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic

$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic

The correct match is:

The paramagnetic complex ion which has no unpaired electrons in $t_{2g}$ orbitals is

Which of the following is an outer orbital complex? (Atomic numbers: $Mn = 25, Fe = 26, Co = 27, Ni = 28$)

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