Which of the following is an outer orbital co | vedclass

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Question

(D) An outer orbital complex is formed when the outer $d$-orbitals $(4d)$ are used in hybridization,typically involving $sp^3d^2$ hybridization.$1$. $

Vedclass · Accepted Answer

$[Ni(NH_3)_6]^{2+}$

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(D) An outer orbital complex is formed when the outer $d$-orbitals $(4d)$ are used in hybridization,typically involving $sp^3d^2$ hybridization.$1$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$2$. $[Mn(CN)_6]^{4-}$: $Mn^{2+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$3$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. It forms $d^2sp^3$ (inner orbital).$4$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. $NH_3$ is a moderate field ligand. It forms $sp^3d^2$ hybridization using $4d$ orbitals,making it an outer orbital complex.

Which of the following is an outer orbital complex? (Atomic numbers: $Mn = 25, Fe = 26, Co = 27, Ni = 28$)

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