Match the following: Column-I Complex Colu | vedclass

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(C) $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. Hybridization is $dsp^2$,resulting in a squa

Vedclass · Accepted Answer

$A$ $B$ $C$   $III$ $II$ $I$

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(C) $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. Hybridization is $dsp^2$,resulting in a square planar,diamagnetic complex. Matches $III$.$[Ni(CO)_4]$: $Ni$ is $3d^8 4s^2$. $CO$ is a strong field ligand,causing pairing of electrons. Hybridization is $sp^3$,resulting in a tetrahedral,diamagnetic complex. Matches $II$.$[NiCl_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $Cl^-$ is a weak field ligand,no pairing occurs. Hybridization is $sp^3$,resulting in a tetrahedral,paramagnetic complex. Matches $I$.Therefore,the correct match is $A-III, B-II, C-I$.

Column-$I$ Complex	Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$	$I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$	$II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$	$III$. Square planar / Diamagnetic

Column $I$	Column $II$
$(A)$ $sp^3$	$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$	$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$	$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$	$(iv)$ $[CoF_6]^{3-}$
	$(v)$ $[Fe(CO)_5]$

Match the following:

Column-$I$ Complex Column-$II$ Structure / Geometry / Property

$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic

$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic

$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic

The correct match is:

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Match the following: Column-$I$ Complex Column-$II$ Structure / Geometry / Property $A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic $B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic $C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic The correct match is: