The number of four-letter words that can be formed using the letters of the word $BARRACK$ is

  • A
    $144$
  • B
    $120$
  • C
    $264$
  • D
    $270$

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Similar Questions

The number of $9$-digit even natural numbers formed using only the digits $0$ and $1$,such that no two consecutive digits are $0$,is:

$A$ test containing $3$ objective-type questions is conducted in a class. Each question has $4$ options and only one option is the correct answer. No two students of the class have answered identically,and no student has written all correct answers. If every student has attempted all the questions,then the maximum possible number of students who have written the test is:

Match the items of List-$I$ to the items of List-$II$:
List-$I$ List-$II$
$(A)$ The number of ways of not selecting $(n-r)$ things from $n$ different things $(I)$ $1+n+{ }^n C_2+\ldots+{ }^n C_r$
$(B)$ $(n-r+1) \cdot{ }^n C_{r-1}$ $(II)$ $(r+1) \cdot{ }^n C_{r+1}$
$(C)$ The number of ways of selecting at least $(n-r)$ things from $n$ different things $(III)$ $r\left({ }^n C_r\right)$
$(D)$ $(n-r)\left({ }^{n-1} C_{r-1}+{ }^{n-1} C_r\right)$ $(IV)$ $2^n-1-n-{ }^n C_2-\ldots-{ }^n C_r$
$(V)$ ${ }^n C_{n-r}$

The correct match is:

If a number is chosen at random from the four-digit numbers formed by using the digits $0, 1, 2, 3, 4, 6$ without repetition,then the probability that it is divisible by $4$ is

The remainder obtained when $1! + 2! + 3! + \ldots + 11!$ is divided by $12$ is

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