The number of arrangements of the letters of the word $SATAYPAUL$ such that no two $A$ are together and middle letter is consonant, is
The number of arrangements of the letters of the word $SATAYPAUL$ such that no two $A$ are together and middle letter is consonant, is
- A
$(5!)^2$
- B
$5!6!$
- C
$5!4!$
- D
$(60) × 5!$
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