The normal to the circle ${x^2} + {y^2} - 3x - 6y - 10 = 0$at the point $(-3, 4)$, is
$2x + 9y - 30 = 0$
$9x - 2y + 35 = 0$
$2x - 9y + 30 = 0$
$2x - 9y - 30 = 0$
Match the statements in Column $I$ with the properties Column $II$ and indicate your answer by darkening the appropriate bubbles in the $4 \times 4$ matrix given in the $ORS$.
Column $I$ | Column $II$ |
$(A)$ Two intersecting circles | $(p)$ have a common tangent |
$(B)$ Two mutually external circles | $(q)$ have a common normal |
$(C)$ two circles, one strictly inside the other | $(r)$ do not have a common tangent |
$(D)$ two branches of a hyperbola | $(s)$ do not have a common normal |
If the line $x = k$ touches the circle ${x^2} + {y^2} = 9$, then the value of $k$ is
An infinite number of tangents can be drawn from $(1, 2)$ to the circle ${x^2} + {y^2} - 2x - 4y + \lambda = 0$, then $\lambda = $
Tangent to the circle $x^2 + y^2$ = $5$ at the point $(1, -2)$ also touches the circle $x^2 + y^2 -8x + 6y + 20$ = $0$ . Then its point of contact is
The line $3x - 2y = k$ meets the circle ${x^2} + {y^2} = 4{r^2}$ at only one point, if ${k^2}$=