The normal to the circle ${x^2} + {y^2} - 3x - 6y - 10 = 0$at the point $(-3, 4)$, is

  • A

    $2x + 9y - 30 = 0$

  • B

    $9x - 2y + 35 = 0$

  • C

    $2x - 9y + 30 = 0$

  • D

    $2x - 9y - 30 = 0$

Similar Questions

Match the statements in Column $I$ with the properties Column $II$ and indicate your answer by darkening the appropriate bubbles in the $4 \times 4$ matrix given in the $ORS$.

Column $I$ Column $II$
$(A)$ Two intersecting circles $(p)$ have a common tangent
$(B)$ Two mutually external circles $(q)$ have a common normal
$(C)$ two circles, one strictly inside the other $(r)$ do not have a common tangent
$(D)$ two branches of a hyperbola $(s)$ do not have a common normal

  • [IIT 2007]

If the line $x = k$ touches the circle ${x^2} + {y^2} = 9$, then the value of $k$ is

An infinite number of tangents can be drawn from $(1, 2)$ to the circle ${x^2} + {y^2} - 2x - 4y + \lambda = 0$, then $\lambda = $

Tangent to the circle $x^2 + y^2$ = $5$ at the point $(1, -2)$ also touches the circle $x^2 + y^2 -8x + 6y + 20$ = $0$ . Then its point of contact is 

The line $3x - 2y = k$ meets the circle ${x^2} + {y^2} = 4{r^2}$ at only one point, if ${k^2}$=