If the line x = k touches the circle x^2 + y^ | vedclass

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(C) The equation of the circle is $x^2 + y^2 = 9$,which represents a circle centered at $(0, 0)$ with radius $r = \sqrt{9} = 3$.For a line $x = k$ to

Vedclass · Accepted Answer

$3$ or $-3$

Vedclass · Answer

(C) The equation of the circle is $x^2 + y^2 = 9$,which represents a circle centered at $(0, 0)$ with radius $r = \sqrt{9} = 3$.For a line $x = k$ to be tangent to the circle,the perpendicular distance from the center $(0, 0)$ to the line $x - k = 0$ must be equal to the radius $r$.The perpendicular distance $d$ is given by $d = \frac{|0 - k|}{\sqrt{1^2 + 0^2}} = |k|$.Setting $d = r$,we get $|k| = 3$,which implies $k = 3$ or $k = -3$.Therefore,the correct value of $k$ is $3$ or $-3$.

If the line $x = k$ touches the circle $x^2 + y^2 = 9$,then the value of $k$ is

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