The negation of the statement pattern p vee ( | vedclass

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(D) To find the negation of the statement $p \vee (q \rightarrow \sim r)$,we apply De Morgan's Law: $\sim(p \vee (q$ $\rightarrow \sim r)) \equiv \sim

Vedclass · Accepted Answer

$\sim p \wedge (q \wedge r)$

Vedclass · Answer

(D) To find the negation of the statement $p \vee (q \rightarrow \sim r)$,we apply De Morgan's Law: $\sim(p \vee (q$ $\rightarrow \sim r)) \equiv \sim p \wedge \sim(q$ $\rightarrow \sim r)$.Using the logical equivalence $\sim(A \rightarrow B) \equiv A \wedge \sim B$,we get $\sim(q \rightarrow \sim r) \equiv q \wedge \sim(\sim r)$.Since $\sim(\sim r) \equiv r$,the expression simplifies to $q \wedge r$.Therefore,the final negation is $\sim p \wedge (q \wedge r)$.

The negation of the statement pattern $p \vee (q \rightarrow \sim r)$ is

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