The negation of p wedge (q rightarrow sim r) | vedclass

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(D) We need to find the negation of the statement $p \wedge (q \rightarrow \sim r)$.Using De Morgan's Law,$\sim(A \wedge B) = \sim A \vee \sim B$:$\si

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$\sim p \vee (q \wedge r)$

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(D) We need to find the negation of the statement $p \wedge (q \rightarrow \sim r)$.Using De Morgan's Law,$\sim(A \wedge B) = \sim A \vee \sim B$:$\sim(p \wedge (q$ $\rightarrow \sim r)) = \sim p \vee \sim(q$ $\rightarrow \sim r)$Using the implication rule $\sim(A \rightarrow B) = A \wedge \sim B$:$\sim p \vee (q \wedge \sim(\sim r))$Using the double negation law $\sim(\sim r) = r$:$\sim p \vee (q \wedge r)$Thus,the correct option is $D$.

The negation of $p \wedge (q \rightarrow \sim r)$ is

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