The negation of the expression q vee ((sim q) | vedclass

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(A) We need to find the negation of the expression $q \vee ((\sim q) \wedge p)$.Let $E = q \vee ((\sim q) \wedge p)$.Using De Morgan's Law,$\sim(A \ve

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$(\sim p) \wedge (\sim q)$

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(A) We need to find the negation of the expression $q \vee ((\sim q) \wedge p)$.Let $E = q \vee ((\sim q) \wedge p)$.Using De Morgan's Law,$\sim(A \vee B) = (\sim A) \wedge (\sim B)$:$\sim E = \sim q \wedge \sim((\sim q) \wedge p)$Using De Morgan's Law again,$\sim(A \wedge B) = (\sim A) \vee (\sim B)$:$\sim E = \sim q \wedge (q \vee \sim p)$Using the Distributive Law,$A \wedge (B \vee C) = (A \wedge B) \vee (A \wedge C)$:$\sim E = (\sim q \wedge q) \vee (\sim q \wedge \sim p)$Since $(\sim q \wedge q)$ is a contradiction $(F)$:$\sim E = F \vee (\sim q \wedge \sim p)$Since $F \vee X = X$:$\sim E = (\sim q \wedge \sim p)$.

The negation of the expression $q \vee ((\sim q) \wedge p)$ is equivalent to

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