The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to
$(\sim p ) \wedge(\sim q)$
$p \wedge(\sim q )$
$(\sim p ) \vee(\sim q)$
$(\sim p ) \vee q$
Consider the following statements
$P :$ Suman is brilliant
$Q :$ Suman is rich
$R :$ Suman is honest
The negation of the statement "Suman is brilliant and dishonest if and only if Suman is rich" can be expressed as
The compound statement $(\mathrm{P} \vee \mathrm{Q}) \wedge(\sim \mathrm{P}) \Rightarrow \mathrm{Q}$ is equivalent to:
Which of the following is not a statement
Which of the following statements is $NOT$ logically equivalent to $\left( {p \to \sim p} \right) \to \left( {p \to q} \right)$?
Which of the following is equivalent to the Boolean expression $\mathrm{p} \wedge \sim \mathrm{q}$ ?