The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to

  • [JEE MAIN 2023]
  • A

    $(\sim p ) \wedge(\sim q)$

  • B

    $p \wedge(\sim q )$

  • C

    $(\sim p ) \vee(\sim q)$

  • D

    $(\sim p ) \vee q$

Similar Questions

Consider the following statements 

$P :$ Suman is brilliant

$Q :$ Suman is rich

$R :$ Suman is honest

The negation of the statement "Suman is brilliant and dishonest if and only if Suman is rich" can be expressed as 

  • [AIEEE 2011]

The compound statement $(\mathrm{P} \vee \mathrm{Q}) \wedge(\sim \mathrm{P}) \Rightarrow \mathrm{Q}$ is equivalent to:

  • [JEE MAIN 2021]

Which of the following is not a statement

Which of the following  statements is $NOT$  logically equivalent to $\left( {p \to  \sim p} \right) \to \left( {p \to q} \right)$?

Which of the following is equivalent to the Boolean expression $\mathrm{p} \wedge \sim \mathrm{q}$ ?

  • [JEE MAIN 2021]