The negation of sim s vee (sim r wedge s) is | vedclass

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Question

(D) We need to find the negation of the expression $\sim s \vee (\sim r \wedge s)$.Using De Morgan's Law,$\sim (p \vee q) \equiv \sim p \wedge \sim q$

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$s \wedge r$

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(D) We need to find the negation of the expression $\sim s \vee (\sim r \wedge s)$.Using De Morgan's Law,$\sim (p \vee q) \equiv \sim p \wedge \sim q$:$\sim (\sim s \vee (\sim r \wedge s)) \equiv \sim (\sim s) \wedge \sim (\sim r \wedge s)$Using the Double Negation Law,$\sim (\sim s) \equiv s$:$\equiv s \wedge \sim (\sim r \wedge s)$Applying De Morgan's Law again,$\sim (p \wedge q) \equiv \sim p \vee \sim q$:$\equiv s \wedge (\sim (\sim r) \vee \sim s)$Using the Double Negation Law,$\sim (\sim r) \equiv r$:$\equiv s \wedge (r \vee \sim s)$Using the Distributive Law,$p \wedge (q \vee r) \equiv (p \wedge q) \vee (p \wedge r)$:$\equiv (s \wedge r) \vee (s \wedge \sim s)$Since $s \wedge \sim s \equiv F$ (Contradiction Law):$\equiv (s \wedge r) \vee F$Using the Identity Law,$p \vee F \equiv p$:$\equiv s \wedge r$

The negation of $\sim s \vee (\sim r \wedge s)$ is equivalent to

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