$( S 1)( p \Rightarrow q ) \vee( p \wedge(\sim q ))$ is a tautology $( S 2)((\sim p ) \Rightarrow(\sim q )) \wedge((\sim p ) \vee q )$ is a Contradiction. Then

  • [JEE MAIN 2023]
  • A

    only $(S2)$ is correct

  • B

    both $(S1)$ and $(S2)$ are correct

  • C

    both $(S1)$ and $(S2)$ are wrong

  • D

    only $(S1)$ is correct

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