The molecule in which hybrid $MOs$ involve only one $d-$orbital of the central atom is:
- A$[Ni(CN)_{4}]^{2-}$
- B$[CrF_{6}]^{3-}$
- C$BrF_{5}$
- D$XeF_{4}$
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Similar Questions
The magnetic moment of $[NiX_4]^{2-}$ ion is found to be zero. Then the ion is : ($X =$ monodentate anionic ligand)
Medium
View SolutionThe number of unpaired electrons in $Ni(CO)_4$ is
MediumAIIMS 1997
View SolutionMatch the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$ $B. dsp^2$ $(ii). [Ni(CO)_4]$ $C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$ $D. d^2sp^3$ $(iv). [CoF_6]^{3-}$ $(v). [Fe(CO)_5]$
| $A. sp^3$ | $(i). [Co(NH_3)_6]^{3+}$ |
| $B. dsp^2$ | $(ii). [Ni(CO)_4]$ |
| $C. sp^3d^2$ | $(iii). [Pt(NH_3)_2Cl_2]$ |
| $D. d^2sp^3$ | $(iv). [CoF_6]^{3-}$ |
| $(v). [Fe(CO)_5]$ |
The $[Co(H_2O)_6]^{2+}$ ion has three unpaired electrons. The hybridization of $Co$ in $[Co(H_2O)_6]^{2+}$ is
MediumNEET 2017
View SolutionSelect the incorrect match.
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