(A) We know that the range of the sine function is $-1 \leq \sin x \leq 1$. To find the minimum value of $f(x) = 1 - \sin x$,we need to subtract the m

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(A) We know that the range of the sine function is $-1 \leq \sin x \leq 1$. To find the minimum value of $f(x) = 1 - \sin x$,we need to subtract the maximum possible value of $\sin x$ from $1$. Since the maximum value of $\sin x$ is $1$,we have: $f_{\min} = 1 - (\sin x)_{\max} = 1 - 1 = 0$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Maximum and minimum values of trigonometrical functions, Conditional trigonometrical identities

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The minimum value of $1-\sin x$ is

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A
$0$
B
$-1$
C
$1$
D
$2$

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Class 11

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Trigonometrical Ratios, Functions and Identities

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Maximum and minimum values of trigonometrical functions, Conditional trigonometrical identities

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