The mean deviation from the median for the fo | vedclass

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(A) First,we calculate the cumulative frequency $(cf)$ and the median $(M)$:$x_i$$f_i$$cf$$|x_i - M|$$f_i|x_i - M|$$10$$6$$6$$|10-12|=2$$12$$11$$12$$1

Vedclass · Accepted Answer

$0.75$

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(A) First,we calculate the cumulative frequency $(cf)$ and the median $(M)$:$x_i$$f_i$$cf$$|x_i - M|$$f_i|x_i - M|$$10$$6$$6$$|10-12|=2$$12$$11$$12$$18$$|11-12|=1$$12$$12$$18$$36$$|12-12|=0$$0$$13$$12$$48$$|13-12|=1$$12$Total frequency $N = \sum f_i = 6 + 12 + 18 + 12 = 48$.The median is the value corresponding to the $\frac{N}{2} = \frac{48}{2} = 24$th observation. Looking at the $cf$ column,the $24$th observation falls in the class where $x = 12$. Thus,$M = 12$.The mean deviation about the median is given by:$MD = \frac{\sum f_i|x_i - M|}{N} = \frac{12 + 12 + 0 + 12}{48} = \frac{36}{48} = 0.75$.

$x_i$	$2$	$4$	$5$	$7$	$9$
$f_i$	$2$	$4$	$10$	$8$	$6$

Income per day	Number of persons
$0-100$	$4$
$100-200$	$8$
$200-300$	$9$
$300-400$	$10$
$400-500$	$7$
$500-600$	$5$
$600-700$	$4$
$700-800$	$3$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Freq	$6$	$7$	$15$	$16$	$4$	$2$

The mean deviation from the median for the following data is:
$x$ $10$ $11$ $12$ $13$
$f$ $6$ $12$ $18$ $12$

Similar Questions

The mean deviation about the mean for the following data is:
$x_i$ $2$ $4$ $5$ $7$ $9$
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Find the mean deviation about the mean for the following data:
Income per day Number of persons
$0-100$ $4$
$100-200$ $8$
$200-300$ $9$
$300-400$ $10$
$400-500$ $7$
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The mean deviation of the numbers $a, a+d, a+2d, \ldots, a+2nd$ from their mean is equal to

Calculate the mean deviation about the median for the following data:
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Freq $6$ $7$ $15$ $16$ $4$ $2$

Find the mean deviation about the mean for the following data: $12, 3, 18, 17, 4, 9, 17, 19, 20, 15, 8, 17, 2, 3, 16, 11, 3, 1, 0, 5$.

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The mean deviation from the median for the following data is:$x$$10$$11$$12$$13$$f$$6$$12$$18$$12$