The mean deviation about the mean for the fol | vedclass

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(D) First,we calculate the class marks $(x_i)$ and the mean $(\bar{x})$:Class interval$x_i$$f_i$$f_i x_i$$|x_i - \bar{x}|$$f_i |x_i - \bar{x}|$$0-2$$1

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$\frac{20}{13}$

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(D) First,we calculate the class marks $(x_i)$ and the mean $(\bar{x})$:Class interval$x_i$$f_i$$f_i x_i$$|x_i - \bar{x}|$$f_i |x_i - \bar{x}|$$0-2$$1$$1$$1$$4$$4$$2-4$$3$$3$$9$$2$$6$$4-6$$5$$5$$25$$0$$0$$6-8$$7$$3$$21$$2$$6$$8-10$$9$$1$$9$$4$$4$Total$13$$65$$20$The mean is $\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{65}{13} = 5$.The mean deviation about the mean is $\frac{\sum f_i |x_i - \bar{x}|}{\sum f_i} = \frac{20}{13}$.

$\text{Marks obtained}$	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
$\text{Number of Boys}$	$6$	$8$	$10$	$4$	$2$

The mean deviation about the mean for the following data is
Class interval Frequency
$0-2$ $1$
$2-4$ $3$
$4-6$ $5$
$6-8$ $3$
$8-10$ $1$

Similar Questions

The mean deviation about the mean for the following data is:
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$\text{Number of Boys}$ $6$ $8$ $10$ $4$ $2$

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Class interval	Frequency
$0-2$	$1$
$2-4$	$3$
$4-6$	$5$
$6-8$	$3$
$8-10$	$1$

The mean deviation about the mean for the following data isClass intervalFrequency$0-2$$1$$2-4$$3$$4-6$$5$$6-8$$3$$8-10$$1$