The mean deviation about the mean for the following data is:

$\text{Marks obtained}$	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
$\text{Number of Boys}$	$6$	$8$	$10$	$4$	$2$

The mean deviation from the median for the following data is:

$x$	$10$	$11$	$12$	$13$
$f$	$6$	$12$	$18$	$12$

The mean and variance of $10$ observations are $9$ and $34.2$,respectively. If $8$ of these observations are $2, 3, 5, 10, 11, 13, 15, 21$,then the mean deviation about the median of all the $10$ observations is

The mean deviation about the mean for the data:

$x_i$	$5$	$7$	$9$	$10$	$12$	$15$
$f_i$	$8$	$6$	$2$	$2$	$2$	$6$

is equal to: (in /$13$)

If $M_1$ is the mean deviation from the mean of the discrete data $44, 5, 27, 20, 8, 54, 9, 14, 35$ and $M_2$ is the mean deviation from the median of the same data,then $M_1 - M_2 =$

The mean deviation about the median of the numbers $2, 3, 5, 20, 17, 15, 13, 11, 9, 7$ is