The mass number of an iodine nucleus and a po | vedclass

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(A) The radius $R$ of a nucleus with mass number $A$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant.Given the mass numbers for io

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$5: 6$

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(A) The radius $R$ of a nucleus with mass number $A$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant.Given the mass numbers for iodine $(A_i = 125)$ and polonium $(A_p = 216)$.The ratio of the radii is given by $\frac{R_i}{R_p} = \frac{R_0 A_i^{1/3}}{R_0 A_p^{1/3}} = \left( \frac{A_i}{A_p} \right)^{1/3}$.Substituting the given values: $\frac{R_i}{R_p} = \left( \frac{125}{216} \right)^{1/3}$.Since $125 = 5^3$ and $216 = 6^3$,we have $\frac{R_i}{R_p} = \frac{5}{6}$.Therefore,the ratio is $5:6$.

The mass number of an iodine nucleus and a polonium nucleus is $125$ and $216$ respectively. The ratio of the radius of the iodine nucleus to that of the polonium nucleus is:

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