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(A) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - \omega^2 R \cos^2 \lambda$. At the equat

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(A) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by the formula: $g' = g - \omega^2 R \cos^2 \lambda$. At the equator,the latitude $\lambda = 0^\circ$,so $\cos 0^\circ = 1$. Thus,the effective gravity at the equator is $g_{eq} = g - \omega^2 R$. If the earth stops rotating,the angular velocity $\omega$ becomes $0$. Consequently,the term $\omega^2 R$ becomes $0$,and the value of $g$ at the equator becomes $g_{eq} = g$. Since $g$ is greater than $(g - \omega^2 R)$,the value of $g$ at the equator will increase.

If the earth stops rotating,the value of $g$ at the equator will

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