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(C) The reaction sequence is an example of Hofmann elimination.$1$. The amine $(CH_3)_2CHCH_2N(CH_2CH_3)_2$ reacts with excess $CH_3I$ to form the qua

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$(CH_3)_2CHCH_2N(CH_3)CH_2CH_3 + H_2C = CH_2$

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(C) The reaction sequence is an example of Hofmann elimination.$1$. The amine $(CH_3)_2CHCH_2N(CH_2CH_3)_2$ reacts with excess $CH_3I$ to form the quaternary ammonium salt $(CH_3)_2CHCH_2N(CH_2CH_3)_2(CH_3)^+ I^-$.$2$. Treatment with $Ag_2O/H_2O$ converts the iodide salt into the corresponding quaternary ammonium hydroxide $(CH_3)_2CHCH_2N(CH_2CH_3)_2(CH_3)^+ OH^-$.$3$. Upon heating,the Hofmann elimination occurs. The base (hydroxide) abstracts a $\beta$-hydrogen from the ethyl group (which is less sterically hindered than the isobutyl group),leading to the formation of ethene $(H_2C=CH_2)$ and the tertiary amine $(CH_3)_2CHCH_2N(CH_3)CH_2CH_3$.

The major products obtained from the following sequence of reactions are
$(CH_3)_2CHCH_2N(CH_2CH_3)_2$ $\xrightarrow{CH_3I}$ $\xrightarrow[H_2O]{Ag_2O}$ $\xrightarrow{\Delta} \text{products}$

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The major products obtained from the following sequence of reactions are$(CH_3)_2CHCH_2N(CH_2CH_3)_2$ $\xrightarrow{CH_3I}$ $\xrightarrow[H_2O]{Ag_2O}$ $\xrightarrow{\Delta} \text{products}$