The major product formed in the following rea | vedclass

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(C) Step $1$: Dehydrohalogenation of $C_6H_5-CHBr-CH_2Br$ with $alc. KOH$ followed by $NaNH_2$ leads to the formation of phenylacetylene $(C_6H_5-C \e

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$1,3,5-$triphenylbenzene

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(C) Step $1$: Dehydrohalogenation of $C_6H_5-CHBr-CH_2Br$ with $alc. KOH$ followed by $NaNH_2$ leads to the formation of phenylacetylene $(C_6H_5-C \equiv CH)$.Step $2$: The cyclic trimerization of phenylacetylene occurs when passed through a red hot iron tube at $873 \ K$.Step $3$: The trimerization of $C_6H_5-C \equiv CH$ yields $1,3,5-triphenylbenzene$ as the major product due to steric hindrance,which favors the meta-substituted product.

The major product formed in the following reaction sequence is:
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$

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The major product formed in the following reaction sequence is:$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$