The major product 'P' formed in this reaction | vedclass

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Question

(C) The given reactant is $2,2'$-diformylbiphenyl. Since both aldehyde groups are attached to the biphenyl system and lack $\alpha$-hydrogens,they und

Vedclass · Accepted Answer

$2-$(hydroxymethyl)biphenyl-$2$'-carboxylic acid

Vedclass · Answer

(C) The given reactant is $2,2'$-diformylbiphenyl. Since both aldehyde groups are attached to the biphenyl system and lack $\alpha$-hydrogens,they undergo an intramolecular Cannizzaro reaction in the presence of a base $(	ext{OH}^-)$. One aldehyde group is reduced to a primary alcohol $(-CH_2OH)$ and the other is oxidized to a carboxylate group $(-COO^-)$. Upon acidic workup $(	ext{H}^+)$,the carboxylate group is protonated to form a carboxylic acid $(-COOH)$. Thus,the product is $2$-(hydroxymethyl)biphenyl-$2'$-carboxylic acid.

The major product $'P'$ formed in this reaction is:

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