Identify the correct option regarding the dis | vedclass

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(B) Option $(B)$ is correct. $PhCHO$ (Benzaldehyde) does not contain an $\alpha$-methyl group,so it does not give a positive Tollen's test for silver

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Pair of compounds: $(I) PhCHO, (II) CH_3CHO$. Reagent: Tollen's reagent $(AgNO_3 + NH_4OH)$. Response: $(II)$ forms a silver mirror,$(I)$ does not.

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(B) Option $(B)$ is correct. $PhCHO$ (Benzaldehyde) does not contain an $\alpha$-methyl group,so it does not give a positive Tollen's test for silver mirror formation in the same way as aliphatic aldehydes,but more importantly,$CH_3CHO$ (Acetaldehyde) is an aliphatic aldehyde that readily reduces Tollen's reagent to form a silver mirror. Option $(A)$ is incorrect because $HCHO$ does not have an $\alpha$-methyl group and does not give the iodoform test,while $CH_3CHO$ does. Option $(C)$ is incorrect because both glucose and fructose react with bromine water (fructose isomerizes to glucose in basic/neutral conditions or reacts via enediol). Option $(D)$ is incorrect because $2,4-DNP$ reacts with all carbonyl compounds (aldehydes and ketones),so it cannot distinguish between them.

Identify the correct option regarding the distinction between pairs of compounds.

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