What are Y and Z respectively in the given re | vedclass

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(B) $1$. The starting material is propene $(CH_3CH=CH_2)$.$2$. Hydroboration-oxidation of propene with $(i) B_2H_6$ and $(ii) H_2O_2/NaOH$ gives propa

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$CH_3CH_2CHO, CH_3CH_2CH=C(CH_3)CHO$

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(B) $1$. The starting material is propene $(CH_3CH=CH_2)$.$2$. Hydroboration-oxidation of propene with $(i) B_2H_6$ and $(ii) H_2O_2/NaOH$ gives propan$-1-$ol $(CH_3CH_2CH_2OH)$ as $X$.$3$. Dehydrogenation of propan$-1-$ol $(X)$ using $Cu$ at $573 \ K$ gives propanal $(CH_3CH_2CHO)$ as $Y$.$4$. Propanal $(Y)$ undergoes aldol condensation in the presence of dilute $NaOH$ followed by heating $(\Delta)$ to give the $\alpha,\beta$-unsaturated aldehyde,$2$-methylpent-$2$-enal $(CH_3CH_2CH=C(CH_3)CHO)$ as $Z$.

Column-$I$ (Example)	Column-$II$ (Reaction)
$(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$	$(1)$ Friedel-Crafts acylation
$(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$	$(2)$ $HVZ$ reaction
$(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$	$(3)$ Aldol condensation
$(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$	$(4)$ Cannizzaro's reaction
$(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$	$(5)$ Rosenmund's reduction
$(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$	$(6)$ Stephen's reaction

What are $Y$ and $Z$ respectively in the given reaction sequence?

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