The magnitude of the electric force on a 2, m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The distance from the center $O$ to each vertex of the equilateral triangles is $r = \frac{a}{\sqrt{3}} = \frac{10\, cm}{\sqrt{3}} = \frac{0.1}{\s

Vedclass · Accepted Answer

$43.2$

Vedclass · Answer

(D) The distance from the center $O$ to each vertex of the equilateral triangles is $r = \frac{a}{\sqrt{3}} = \frac{10\, cm}{\sqrt{3}} = \frac{0.1}{\sqrt{3}}\, m$.Let $q = 2\, \mu C = 2 	imes 10^{-6}\, C$ be the charge at the center $O$ and $q_0 = 2\, \mu C$ be the magnitude of the charges at the vertices.The force due to each charge at the center is $F = \frac{k q q_0}{r^2} = \frac{9 	imes 10^9 	imes (2 	imes 10^{-6})^2}{(0.1/\sqrt{3})^2} = \frac{9 	imes 10^9 	imes 4 	imes 10^{-12}}{0.01/3} = 36 	imes 10^{-3} 	imes 300 = 10.8\, N$.Looking at the symmetry,the forces from $A, B, C$ (positive) and $D, E, F$ (negative) act on the central charge $q$. Charges $A, B, C$ attract the negative charge or repel the positive charge. Since the central charge is positive $(2\, \mu C)$,it is repelled by $A, B, C$ and attracted by $D, E, F$.The vectors of these forces point towards the vertices $D, E, F$ and away from $A, B, C$. Summing these vectors,we find the resultant force $F_{net} = 4F = 4 	imes 10.8 = 43.2\, N$.

Similar Questions

What is the force between two small charged spheres having charges of $2 \times 10^{-7} C$ and $3 \times 10^{-7} C$ placed $30 cm$ apart in air?

When air is replaced by a dielectric medium of constant $K$,the maximum force of attraction between two charges separated by distance '$d$' is . . . . . . .

$A$ charged particle of mass $m_{1}$ and charge $q_{1}$ is revolving in a circle of radius $r$. Another charged particle of charge $q_{2}$ and mass $m_{2}$ is situated at the centre of the circle. If the velocity and time period of the revolving particle are $v$ and $T$ respectively,then:

Two unit negative charges are placed on a straight line. $A$ positive charge $q$ is placed exactly at the midpoint between these unit charges. If the system of these three charges is in equilibrium,the value of $q$ (in $C$) is

Two identical tennis balls each having mass $m$ and charge $q$ are suspended from a fixed point by threads of length $l$. What is the equilibrium separation when each thread makes a small angle $\theta$ with the vertical?

Vedclass Test Series

Exam Paper Generator

Online Exam Module