The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of earth’s magnetic field $0.34 \times {10^{ - 4}}\,T$ is along the plane of the coil. The magnetic intensity is
$1.96 \times {10^{ - 4}}\,T$
$1.96 \times {10^{ - 5}}\,T$
$1.96 \times {10^{ 4}}\,T$
$1.96 \times {10^{ 5}}\,T$
If a magnet is suspended at an angle $30^o$ to the magnetic meridian, it makes an angle of $45^o$ with the horizontal. The real dip is
At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively
At which place, earth's magnetism become horizontal
A magnet hung at $45^{\circ}$ with magnetic meridian makes an angle of $60^{\circ}$ with the horizontal. The actual value of the angle of dip is.
The value of horizontal component of earth's magnetic field at a place is $0.35 \times 10^{-4} \,T$. If the angle of dip is $60^{\circ}$, the value of vertical component of earth's magnetic field is nearly ............. $\times 10^{-4} \,T$