The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of the earth's magnetic field is $0.34 \times 10^{-4}\,T$ which is along the plane of the coil. The magnetic field due to magnet is
$1.96 \times 10^{-4}\,T$
$1.96 \times 10^{-5}\,T$
$1.96 \times 10^{4}\,T$
$1.96 \times 10^{5}\,T$
The horizontal component of the earth's magnetic field at any place is $0.36 \times 10^{-4} Wb / m ^{2}$. If the angle of dip at that place is $60^{\circ}$, then the value of vertical component of the earth's magnetic field will be ........ $\times 10^{-4}\;W b / m^{2}$
At a certain place, the horizontal component ${B_0}$ and the vertical component ${V_0}$ of the earth's magnetic field are equal in magnitude. The total intensity at the place will be
The relations amongst the three elements elements earth's magnettic fleld, namely horizontal component $H$, vertical component $V$ and dip $\delta$ are, $( B_{E}=$ total magnetic fleld)
The angle between the earth's magnetic and the earth's geographical axes is....$^o$
The value of the horizontal component of the earth's magnetic field and angle of dip are $1.8 \times {10^{ - 5}}\,Weber/{m^2}$ and $30°$ respectively at some place. The total intensity of earth's magnetic field at that place will be