The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of the earth's magnetic field is $0.34 \times 10^{-4}\,T$ which is along the plane of the coil. The magnetic field due to magnet is
$1.96 \times 10^{-4}\,T$
$1.96 \times 10^{-5}\,T$
$1.96 \times 10^{4}\,T$
$1.96 \times 10^{5}\,T$
The angle of dip is the angle
The angle of dip at a certain place on earth is $60^o$ and the magnitude of earth's horizontal component of magnetic field is $0.26\, G$. The magnetic field at the place on earth is.....$G$
Let $V $ and $H $ be the vertical and horizontal components of earth's magnetic field at any point on earth. Near the north pole
The horizontal component of the earth's magnetic field at any place is $0.36 \times 10^{-4} Wb / m ^{2}$. If the angle of dip at that place is $60^{\circ}$, then the value of vertical component of the earth's magnetic field will be ........ $\times 10^{-4}\;W b / m^{2}$
Give information about the Earth’s magnetic field lines and the location of the magnetic poles.