Two capillary tubes A and B of the same inter | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The height of a liquid column in a capillary tube is given by the formula: $h = \frac{2T \cos 	heta}{r ho g}$.Given that the internal diameters

Vedclass · Accepted Answer

$9:10$

Vedclass · Answer

(B) The height of a liquid column in a capillary tube is given by the formula: $h = \frac{2T \cos 	heta}{r ho g}$.Given that the internal diameters are the same,the radii are equal: $r_A = r_B$.Assuming the angles of contact are nearly equal: $	heta_A = 	heta_B$.Thus,the height $h$ is proportional to $\frac{T}{ho}$,where $T$ is surface tension and $ho$ is density.Therefore,the ratio of the heights is: $\frac{h_A}{h_B} = \frac{T_A}{T_B} 	imes \frac{ho_B}{ho_A}$.Given $\frac{ho_A}{ho_B} = \frac{4}{3}$ and $\frac{T_A}{T_B} = \frac{6}{5}$.Substituting these values: $\frac{h_A}{h_B} = \frac{6}{5} 	imes \frac{3}{4} = \frac{18}{20} = \frac{9}{10}$.So,the ratio is $9:10$.

Similar Questions

Water rises in a capillary tube up to a height of $4 \, cm$. If it is tilted to $30^{\circ}$ from the vertical,then the length of the water column in it will be

The quantity on which the rise of liquid in a capillary tube does not depend is

$A$ long capillary tube of mass $\pi \,g$,radius $2\,mm$ and negligible thickness,is partially immersed in a liquid of surface tension $0.1\,N/m$. Take the angle of contact as zero and neglect the buoyant force of the liquid. Find the force required to hold the tube vertically. $(g = 10\,m/s^2)$

$A$ capillary tube of radius $0.1 \ mm$ is partly dipped in water (surface tension $70 \ dyn/cm$ and glass-water contact angle $\simeq 0^{\circ}$) inclined at $30^{\circ}$ with the vertical. The length of water risen in the capillary is . . . . . . $cm$. (Take $g = 980 \ cm/s^2$)

When a capillary tube is kept in water, water $......$ in the capillary, while when it is kept in mercury, the mercury $......$ in the capillary. (Choose the correct words: $rising up$ / $depressed$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module