The locus of $z$ given by $\left| \frac{z - 1}{z - i} \right| = 1$ is

The minimum value of $|z-1|+|z-5|$ is

If $\left|\frac{z}{1+i}\right|=2$,where $z=x+iy$ and $i=\sqrt{-1}$ represents a circle,then the centre $C$ and radius $r$ of the circle are:

The points in the Argand plane represented by the complex conjugates of $1+2i, 2-3i, 3-4i$:

Let $A, B, C$ be three sets of complex numbers defined as $A = \{z : \text{Im}(z) \ge 1\}$,$B = \{z : |z - 2 - i| = 3\}$,and $C = \{z : \text{Re}((1 - i)z) = \sqrt{2}\}$. If $z$ is any point in $A \cap B \cap C$,then $|z + 1 - i|^2 + |z - 5 - i|^2$ lies between:

The locus of a point $z$ satisfying $|z|^2 = \operatorname{Re}(z)$ is a circle with centre