The locus of a point $z$ satisfying $|z|^2 = \operatorname{Re}(z)$ is a circle with centre

  • A
    $\left(0, \frac{1}{2}\right)$
  • B
    $\left(-\frac{1}{2}, 0\right)$
  • C
    $\left(\frac{1}{2}, 0\right)$
  • D
    $\left(0, -\frac{1}{2}\right)$

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$A$ function $f$ is defined on the complex numbers by $f(z) = (a + ib)z$,where $a, b \in \mathbb{R}^+$. This function has the property that the $f$-image of any point in the complex plane is equidistant from that point and the origin. If $|a + bi| = 10$ and $b^2 = \frac{p}{q}$,where $p, q \in \mathbb{Z}$ and $\text{gcd}(p, q) = 1$,then $p + q$ is:

The locus of the points $z$ which satisfy the condition $\text{arg} \left( \frac{z - 1}{z + 1} \right) = \frac{\pi}{3}$ is

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