The load versus elongation graph for four wir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Young's modulus $Y$ is given by $Y = \frac{FL}{A \Delta l}$,where $F$ is the load,$L$ is the original length,$A$ is the cross-sectional area,a

Vedclass · Accepted Answer

$OA$

Vedclass · Answer

(C) The Young's modulus $Y$ is given by $Y = \frac{FL}{A \Delta l}$,where $F$ is the load,$L$ is the original length,$A$ is the cross-sectional area,and $\Delta l$ is the elongation.Since all wires are of the same material,$Y$ is constant. For wires of the same length $L$,we have $A = \frac{FL}{Y \Delta l}$.For a constant load $F$,the area $A$ is inversely proportional to the elongation $\Delta l$ $(A \propto \frac{1}{\Delta l})$.From the graph,for a given load $F$,the elongation $\Delta l$ is maximum for line $OA$ (i.e.,$\Delta l_A > \Delta l_B > \Delta l_C > \Delta l_D$).Since $A \propto \frac{1}{\Delta l}$,the wire with the maximum elongation will have the minimum cross-sectional area.Therefore,the line $OA$ represents the thinnest wire.

The load versus elongation graph for four wires of the same material is shown in the figure. The thinnest wire is represented by the line

Similar Questions

The length of a metal wire is $l_1$ when the tension in it is $F_1$ and $l_2$ when the tension is $F_2$. Then,the original length of the wire is

What is strain? Give its units. Define longitudinal stress.

$A$ wire can be broken by applying a load of $20 \, kg$ weight. The force required to break the wire of twice the diameter is .......... $kg \, wt$.

What should be the shape of the pillars or columns in buildings and bridges?

$A$ and $B$ are two wires. The radius of $A$ is twice that of $B$. They are stretched by the same load. Then the stress on $B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module