The lines ax^2+2hxy+by^2=0 are at right angle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acute angle $(	heta)$ between the lines represented by the homogeneous equation $ax^2+2hxy+by^2=0$ is given by the formula:$	an 	heta = \le

Vedclass · Accepted Answer

$a+b=0$

Vedclass · Answer

(A) The acute angle $(	heta)$ between the lines represented by the homogeneous equation $ax^2+2hxy+by^2=0$ is given by the formula:$	an 	heta = \left| \frac{2\sqrt{h^2-ab}}{a+b} ight|$If the lines are at right angles (perpendicular),then $	heta = 90^\circ$.Since $	an 90^\circ$ is undefined,the denominator must be zero.Therefore,$a+b=0$.

The lines $ax^2+2hxy+by^2=0$ are at right angles if

Similar Questions

The colour of $KMnO_4$ is due to

The first step of taxonomy is .......... .

If one of the lines $2x^2 - xy + by^2 = 0$ passes through the point $(-4, -2)$,then $b^2 =$

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

Polysaccharides have .............. linkage?

Vedclass Test Series

Exam Paper Generator

Online Exam Module