The colour of KMnO_4 is due to | vedclass

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Question

(A) In $KMnO_4$,the oxidation state of $Mn$ is $+7$. The electronic configuration of $Mn^{7+}$ is $[Ar] 3d^0$. Since there are no electrons in the $d$

Vedclass · Accepted Answer

Charge transfer from ligand to metal

Vedclass · Answer

(A) In $KMnO_4$,the oxidation state of $Mn$ is $+7$. The electronic configuration of $Mn^{7+}$ is $[Ar] 3d^0$. Since there are no electrons in the $d$-orbitals,$d-d$ transition is not possible. The intense purple colour of $KMnO_4$ arises due to the charge transfer from the oxygen ligand to the metal center $(Mn^{7+})$,which is known as ligand-to-metal charge transfer $(LMCT)$.

The colour of $KMnO_4$ is due to

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