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The line $y = mx + c$ touches the parabola $y^2 = 4a(x + a)$ if...

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At what point on the parabola $y^2 = 4x$ does the normal make equal angles with the coordinate axes?

The parabolas $ax^2 + 2bx + cy = 0$ and $dx^2 + 2ex + fy = 0$ intersect on the line $y = 1$. If $a, b, c, d, e, f$ are positive real numbers and $a, b, c$ are in $G.P.$,then

The focus of the parabola $y^2 = 4y - 4x$ is

Find the equation of the parabola with vertex at $(0, 0)$ and focus at $(0, 2)$.

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